\(15\frac{2}{15}-(x-18\frac{4}{5})=6\frac{2}{3}\)
↓
\(\frac{227}{15}-(x-\frac{94}{5})=\frac{20}{3}\)
\(\frac{227}{15}-x+\frac{94}{5}=\frac{20}{3}\)
↓
Приводим к общему знаменателю 15
\(\frac{227}{15}+\frac{282}{15}-x=\frac{100}{15}\)
↓
\(\frac{509}{15}-x=\frac{100}{15}\)
\(\frac{509}{15}-\frac{100}{15}=x\)
↓
\(\frac{409}{15}=x\)
\(27\frac{4}{15}=x\)
Ответ: \(x=27\frac{4}{15}\)