Кружка 1

$V_1 = \pi (5r_2)^2 h_1$

Кружка 2

$V_2 = \pi r_2^2 (2h_1)$

$\frac{V_1}{V_2} = \frac{\pi (5r_2)^2 h_1}{\pi r_2^2 (2h_1)} = \frac{25 \pi r_2^2 h_1}{2 \pi r_2^2 h_1} = \frac{25}{2} = 12.5$